Kaiu Hisayuki + Triumph of Courage

L5R CCG Rules board, 11 April 2008 to 12 April 2008

A topic from AEG's L5R CCG Rules forum, copied for Oracle of the Void from a copy of the forum saved in October 2015, so pages it didn't save are missing. Players' names are left out; the rules officials are named. Rulings are as they stood on these dates; later rulings, the rulebooks and the Rules Archive may differ.

A player, 11 April 2008

viewtopic.php?f=59&t=61939

In this topic, it was stated that since they were separate bonuses, then each one is increased by one I was wondering with Triumph of Courage:Battle: Target an opposed Personality. After each time this turn a Battle action resolves (including this one), give him +1F

Does this give him +2 each time an action is taken?

Also With A legion of one Heroic Battle: Give one of your target Personalities +2F for each unit in the opposing army. If he is a Hero or Deathseeker before the next time this battle a card effect moves him, negate the movement.

Does he get +3 force for each? or do you just add the +1 after calculating the total +2 for each

[Mod edit: Thread title. -ZF]

Brook Cunningham (rules official), 12 April 2008

I was wondering with Triumph of Courage:Battle: Target an opposed Personality. After each time this turn a Battle action resolves (including this one), give him +1F

Does this give him +2 each time an action is taken?

Yes. Because,

1. Each of those bonuses is a seperate, indefinite conditional effect (defined here: http://rules.l5r.com/Effects#Indefinite_conditional_effects).

2. They still all come "from" (per Hisayuki's text) the original action (sources of effects defined here: http://rules.l5r.com/Effects#Source_of_effects).

Also With A legion of one Heroic Battle: Give one of your target Personalities +2F for each unit in the opposing army. If he is a Hero or Deathseeker before the next time this battle a card effect moves him, negate the movement.

Does he get +3 force for each? or do you just add the +1 after calculating the total +2 for each

That answer was contained in the link within the post you linked to, more directly here.